Exercises 9.4 Exercises
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Prove or disprove:
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Find five non-isomorphic groups of order
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List all of the elements of
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Prove that cannot be the internal direct product of two of its proper subgroups.
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Prove that the subgroup of consisting of elements of the form for is an internal direct product isomorphic to
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Prove or disprove: Every nonabelian group of order divisible by 6 contains a subgroup of order
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Let be a group of order If has subgroups and of orders and respectively such that for all and prove that is the internal direct product of and
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Prove or disprove: There is a noncyclic abelian group of order
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Prove or disprove: There is a noncyclic abelian group of order
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Let be a group isomorphism. Show that if and only if where and are the identities of and respectively.
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Let and be isomorphisms. Show that and are both isomorphisms. Using these results, show that the isomorphism of groups determines an equivalence relation on the class of all groups.
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Write out the permutations associated with each element of in the proof of Cayley’s Theorem.
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An automorphism of a group is an isomorphism with itself. Prove that complex conjugation is an automorphism of the additive group of complex numbers; that is, show that the map is an isomorphism from to
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We will denote the set of all automorphisms of by Prove that is a subgroup of the group of permutations of
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Find
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Find
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Let be a group and Define a map by Prove that defines an automorphism of Such an automorphism is called an inner automorphism. The set of all inner automorphisms is denoted by
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Let be a group and Define maps and by and Show that is an automorphism of The isomorphism is called the right regular representation of
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Let be the internal direct product of subgroups and Show that the map defined by for where and is one-to-one and onto.
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Let and be isomorphic groups. If has a subgroup of order prove that must also have a subgroup of order
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55. Groups of order .
- Assume
is a group of order where is an odd prime. If show that must have order or - Suppose that
has an element of order Prove that is isomorphic to Hence, is cyclic. - Suppose that
does not contain an element of order Show that must contain an element of order Hint: Assume that does not contain an element of order - Suppose that
does not contain an element of order Show that must contain an element of order - Let
be a subgroup of with order and have order Show that - Suppose that
does not contain an element of order and is a subgroup of order generated by If is an element of order then for some - Suppose that
does not contain an element of order Prove that is not abelian. - Suppose that
does not contain an element of order and is a subgroup of order generated by and is an element of order Show that we can list the elements of as - Suppose that
does not contain an element of order and is a subgroup of order generated by and is an element of order Prove that the product can be expressed as a uniquely as for some non negative integers Thus, conclude that there is only one possibility for a non-abelian group of order it must therefore be the one we have seen already, the dihedral group.