Prove that the subgroup of \({\mathbb Q}^\ast\) consisting of elements of the form \(2^m 3^n\) for \(m,n \in {\mathbb Z}\) is an internal direct product isomorphic to \({\mathbb Z} \times {\mathbb Z}\text{.}\)
Let \(G\) be a group of order \(20\text{.}\) If \(G\) has subgroups \(H\) and \(K\) of orders \(4\) and \(5\) respectively such that \(hk = kh\) for all \(h \in H\) and \(k \in K\text{,}\) prove that \(G\) is the internal direct product of \(H\) and \(K\text{.}\)
Prove or disprove the following assertion. Let \(G\text{,}\)\(H\text{,}\) and \(K\) be groups. If \(G \times K \cong H \times K\text{,}\) then \(G \cong H\text{.}\)
Let \(\phi : G \rightarrow H\) be a group isomorphism. Show that \(\phi( x) = e_H\) if and only if \(x=e_G\text{,}\) where \(e_G\) and \(e_H\) are the identities of \(G\) and \(H\text{,}\) respectively.
Let \(\phi : G_1 \rightarrow G_2\) and \(\psi : G_2 \rightarrow G_3\) be isomorphisms. Show that \(\phi^{-1}\) and \(\psi \circ \phi\) are both isomorphisms. Using these results, show that the isomorphism of groups determines an equivalence relation on the class of all groups.
An automorphism of a group \(G\) is an isomorphism with itself. Prove that complex conjugation is an automorphism of the additive group of complex numbers; that is, show that the map \(\phi( a + bi ) = a - bi\) is an isomorphism from \({\mathbb C}\) to \({\mathbb C}\text{.}\)
We will denote the set of all automorphisms of \(G\) by \(\aut(G)\text{.}\) Prove that \(\aut(G)\) is a subgroup of \(S_G\text{,}\) the group of permutations of \(G\text{.}\)
Let \(G\) be a group and \(g \in G\text{.}\) Define a map \(i_g : G \rightarrow G\) by \(i_g(x) = g x g^{-1}\text{.}\) Prove that \(i_g\) defines an automorphism of \(G\text{.}\) Such an automorphism is called an inner automorphism. The set of all inner automorphisms is denoted by \(\inn(G)\text{.}\)
Let \(G\) be a group and \(g \in G\text{.}\) Define maps \(\lambda_g :G \rightarrow G\) and \(\rho_g :G \rightarrow G\) by \(\lambda_g(x) = gx\) and \(\rho_g(x) = xg^{-1}\text{.}\) Show that \(i_g = \rho_g \circ \lambda_g\) is an automorphism of \(G\text{.}\) The isomorphism \(g \mapsto \rho_g\) is called the right regular representation of \(G\text{.}\)
Let \(G\) be the internal direct product of subgroups \(H\) and \(K\text{.}\) Show that the map \(\phi : G \rightarrow H \times K\) defined by \(\phi(g) = (h,k)\) for \(g =hk\text{,}\) where \(h \in H\) and \(k \in K\text{,}\) is one-to-one and onto.
Let \(G\) and \(H\) be isomorphic groups. If \(G\) has a subgroup of order \(n\text{,}\) prove that \(H\) must also have a subgroup of order \(n\text{.}\)
Let \(H_1\) and \(H_2\) be subgroups of \(G_1\) and \(G_2\text{,}\) respectively. Prove that \(H_1 \times H_2\) is a subgroup of \(G_1 \times G_2\text{.}\)
Let \(m, n \in {\mathbb Z}\text{.}\) Prove that \(\langle m \rangle \cap \langle n \rangle = \langle l \rangle\) if and only if \(l = \lcm(m,n)\text{.}\)
In this series of exercises we will classify all groups of order \(2p\text{,}\) where \(p\) is an odd prime.
Assume \(G\) is a group of order \(2p\text{,}\) where \(p\) is an odd prime. If \(a \in G\text{,}\) show that \(a\) must have order \(1\text{,}\)\(2\text{,}\)\(p\text{,}\) or \(2p\text{.}\)
Suppose that \(G\) does not contain an element of order \(2p\text{.}\) Show that \(G\) must contain an element of order \(p\text{.}\)Hint: Assume that \(G\) does not contain an element of order \(p\text{.}\)
Suppose that \(G\) does not contain an element of order \(2p\) and \(P = \langle z \rangle\) is a subgroup of order \(p\) generated by \(z\text{.}\) If \(y\) is an element of order \(2\text{,}\) then \(yz = z^ky\) for some \(2 \leq k \lt p\text{.}\)
Suppose that \(G\) does not contain an element of order \(2p\) and \(P = \langle z \rangle\) is a subgroup of order \(p\) generated by \(z\) and \(y\) is an element of order \(2\text{.}\) Show that we can list the elements of \(G\) as \(\{z^iy^j\mid 0\leq i \lt p, 0\leq j \lt 2\}\text{.}\)
Suppose that \(G\) does not contain an element of order \(2p\) and \(P = \langle z \rangle\) is a subgroup of order \(p\) generated by \(z\) and \(y\) is an element of order \(2\text{.}\) Prove that the product \((z^iy^j)(z^ry^s)\) can be expressed as a uniquely as \(z^m y^n\) for some non negative integers \(m, n\text{.}\) Thus, conclude that there is only one possibility for a non-abelian group of order \(2p\text{,}\) it must therefore be the one we have seen already, the dihedral group.